Baldor BC145 Installation And Operating Manual
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Contents
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i. Current Input SignalWarning! Read Safety Warning on Page 1before attempting to use this control.Note: The Voltage/Current (VLT/CUR) jumper must be in “CUR”position. Connect the negative current signal input to terminal “5”and the positive to terminal “6.” The BC145 is factory calibrated sothat a 4 - 20mA signal will provide a 0 - 9 Volt output. The inputrange can be converted to a 10 - 50mA range by attaching a 150Ω1W resistor across the current input terminals “5” and “6.” See fig-ure 3. Control must be recalibrated when the 150Ω resistor is installed. The range of signalinput can be changed to 1 - 5mA by removing resistor R3 from the printed circuit board.Recalibrate the Signal Isolator to follow a 4 - 20mA current signal input as follows:1. Connect a 10V DC meter (digital DC meter is suggested) to terminals “9”(-) & “10” (+).2. Apply the minimum input current (4mA) at terminals “5” and “6.”3. Adjust the “MIN” trimpot to an output voltage of 0 volt DC.4. Set the input current to 20mA and adjust the “MAX” trimpot so that the output voltage is atthe desired level (9V DC).5. Repeat steps 3 and 4 if extreme accuracy is required. The Signal Isolator is now cali-brated to provide 0 - 9V DC output with a 4 - 20mA input.6. Use the “MIN” and “MAX” trimpot if other than 0 - 9V DC output is required with the respec-tive input current range.65 6150Ω Resistor Converts 4 - 20mA to 10 - 50mA+– 4 - 20mAFIGURE 3 – CURRENT INPUTSIGNAL CONNECTION! |
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