www.desatech.com110398-01D 7and ventilation. However, in buildings of un-usually tight construction, you must provideadditional fresh air.Unusually tight construction is definedas construction where:a. walls and ceilings exposed to the out-side atmosphere have a continuouswater vapor retarder with a rating of oneperm (6x10-11 kg per pa-sec-m2) or lesswith openings gasketed or sealed andb. weather stripping has been added onopenable windows and doors andc. caulking or sealants are applied toareas such as joints around windowand door frames, between sole platesand floors, between wall-ceiling joints,between wall panels, at penetrationsfor plumbing, electrical, and gas lines,and at other openings.If your home meets all of the three criteriaabove, you must provide additional fresh air.See Ventilation Air From Outdoors, page 8.If your home does not meet all of the threecriteria above, proceed to Determining Fresh-Air Flow For Heater Location.Confined and Unconfined SpaceThe National Fuel Gas Code, ANSI Z223.1/NFPA 54 defines a confined space as a spacewhose volume is less than 50 cubic feet per1,000 Btu/hr (4.8 m3 per kw) of the aggregateinput rating of all appliances installed in thatspace and an unconfined space as a spacewhose volume is not less than 50 cubic feetper 1,000 Btu/hr (4.8 m3 per kw) of the ag-gregate input rating of all appliances installedin that space. Rooms communicating directlywith the space in which the appliances areinstalled*, through openings not furnishedwith doors, are considered a part of the un-confined space.* Adjoining rooms are communicating only ifthere are doorless passageways or ventilationgrills between them.DETERMINING FRESH-AIR FLOWFOR HEATER LOCATIONDetermining if You Have a Confined orUnconfined SpaceUse this work sheet to determine if you havea confined or unconfined space.Space: Includes the room in which you willinstall heater plus any adjoining rooms withdoorless passageways or ventilation grillsbetween the rooms.1. Determine the volume of the space (lengthx width x height).Length x Width x Height = __________ c u .ft. (volume of space)Example: Space size 20 ft. (length) x 16 ft.(width) x 8 ft. (ceiling height) = 2560 cu. ft.(volume of space)If additional ventilation to adjoining roomis supplied with grills or openings, add thevolume of these rooms to the total volumeof the space.2. Multiply the space volume by 20 to determinethe maximum Btu/Hr the space can sup-port.________ (volume of space) x 20 = (Maxi-mum Btu/Hr the space can support)Example: 2560 cu. ft. (volume of space) x 20= 51,200 (maximum Btu/Hr the space cansupport)3. Add the Btu/Hr of all fuel burning appliancesin the space.Vent-free heater _________Btu/HrGas water heater* _________Btu/HrGas furnace _________Btu/HrVented gas heater _________Btu/HrGas fireplace logs _________Btu/HrOther gas appliances* +_________Btu/HrTotal =_________Btu/Hr* Do not include direct-vent gas appliances.Direct-vent draws combustion air from theoutdoors and vents to the outdoors.Example:Gas water heater* __________ Btu/HrVent-free heater + _________ Btu/HrTotal = _________ Btu/Hr4. Compare the maximum Btu/Hr the spacecan support with the actual amount of Btu/Hrused.________ Btu/Hr (maximum the space cansupport)________ Btu/Hr (actual amount of Btu/Hrused)Example: 51,200 Btu/Hr (maximum thespace can support)73,000 Btu/Hr (actual amount ofBtu/Hr used)AIR FOR COMbUSTION AND VENTILATIONContinued40,00033,00073,000