Desa VMH10TPB Operation And Installation Manual

Also see for EFS10TN: OWNER'S OPERATION AND INSTALLATION MANUAL OWNER'S OPERATION AND INSTALLATION MANUAL OWNER'S OPERATION AND INSTALLATION MANUAL

107032-01JFor more information, visit www.desatech.comFor more information, visit www.desatech.com6AIR FOR COMBUSTION AND VENTILATIONProviding Adequate VentilationDetermining Fresh-Air Flow for Fireplace LocationAIR FOR COMBUSTION ANDVENTILATIONToday’s homes are built more energy efficient than ever. New mate-rials, increased insulation, and new construction methods help reduceheat loss in homes. Home owners weather strip and caulk aroundwindows and doors to keep the cold air out and the warm air in. Duringheating months, home owners want their homes as airtight as possible.While it is good to make your home energy efficient, your homeneeds to breathe. Fresh air must enter your home. All fuel-burningappliances need fresh air for proper combustion and ventilation.Exhaust fans, fireplaces, clothes dryers, and fuel burning appliancesdraw air from the house to operate. You must provide adequate freshair for these appliances. This will insure proper venting of ventedfuel-burning appliances.WARNING: This fireplace shall not be installed ina confined space or unusually tight constructionunless provisions are provided for adequate com-bustion and ventilation air. Read the following in-structions to insure proper fresh air for this andother fuel-burning appliances in your home.PROVIDING ADEQUATE VENTILATIONThe following are excerpts from National Fuel Gas Code, ANSIZ223.1/NFPA 54, Section 5.3, Air for Combustion and Ventilation.All spaces in homes fall into one of the three following ventilationclassifications:1. Unusually Tight Construction2. Unconfined Space3. Confined SpaceThe information on pages 6 through 8 will help you classify yourspace and provide adequate ventilation.Unusually Tight ConstructionThe air that leaks around doors and windows may provide enoughfresh air for combustion and ventilation. However, in buildings ofunusually tight construction, you must provide additional fresh air.Unusually tight construction is defined as constructionwhere:a. walls and ceilings exposed to the outside atmospherehave a continuous water vapor retarder with a ratingof one perm (6 x 10-11 kg per pa-sec-m2 ) or less withopenings gasketed or sealedandb. weather stripping has been added on openable win-dows and doorsandc. caulking or sealants are applied to areas such asjoints around window and door frames, between soleplates and floors, between wall-ceiling joints, betweenwall panels, at penetrations for plumbing, electrical,and gas lines, and at other openings.If your home meets all of these three criteria, youmust provide additional fresh air. SeeVentilation AirFrom Outdoors, page 8.If your home does not meet all of the three criteria above,proceed toDetermining Fresh-Air Flow For FireplaceLocation, below.Confined and Unconfined SpaceThe National Fuel Gas Code, ANSI Z223.1/NFPA 54 defines aconfined space as a space whose volume is less than 50 cubic feetper 1,000 Btu per hour (4.8 m3 per kw) of the aggregate input ratingof all appliances installed in that space and an unconfined space asa space whose volume is not less than 50 cubic feet per 1,000 Btu perhour (4.8 m3 per kw) of the aggregate input rating of all appliancesinstalled in that space. Rooms communicating directly with thespace in which the appliances are installed*, through openings notfurnished with doors, are considered a part of the unconfined space.* Adjoining rooms are communicating only if there are doorlesspassageways or ventilation grills between them.DETERMINING FRESH-AIR FLOW FORFIREPLACE LOCATIONDetermining if You Have a Confined orUnconfined SpaceUse this work sheet to determine if you have a confined or unconfined space.Space: Includes the room in which you will install fireplace plus any adjoiningrooms with doorless passageways or ventilation grills between the rooms.1. Determine the volume of the space (length x width x height).Length x Width x Height = ___________ cu. ft. (volume of space)Example: Space size 16 ft. (length) x 14 ft. (width) x 8 ft. (ceilingheight) = 1792 cu. ft. (volume of space)If additional ventilation to adjoining room is supplied with grills or open-ings, add the volume of these rooms to the total volume of the space.2. Multiply the space volume by 20 to determine the maximum Btu/Hrthe space can support.__________ (volume of space) x 20 = (Maximum Btu/Hr the spacecan support)Example: 1792 cu. ft. (volume of space) x 20 = 35,840 (maximumBtu/Hr the space can support)