GE Multilin L30 Line Current Differential System 5-1095 SETTINGS 5.5 FLEXLOGIC™5The equation for virtual output 4 is:[85] Virt Op 4 On[86] Virt Op 1 On[87] Virt Op 2 On[88] Virt Ip 1 On[89] DIG ELEM 1 PKP[90] XOR(2)[91] Virt Op 3 On[92] OR(4)[93] LATCH (S,R)[94] Virt Op 3 On[95] TIMER 1[96] Cont Ip H1c On[97] OR(3)[98] TIMER 2[99] = Virt Op 4It is now possible to check that the selection of parameters will produce the required logic by converting the set of parame-ters into a logic diagram. The result of this process is shown below, which is compared to the logic for virtual output 4 dia-gram as a check.Figure 5–46: FLEXLOGIC™ EQUATION FOR VIRTUAL OUTPUT 47. Now write the complete FlexLogic™ expression required to implement the logic, making an effort to assemble theequation in an order where Virtual Outputs that will be used as inputs to operators are created before needed. In caseswhere a lot of processing is required to perform logic, this may be difficult to achieve, but in most cases will not causeproblems as all logic is calculated at least four times per power frequency cycle. The possibility of a problem caused bysequential processing emphasizes the necessity to test the performance of FlexLogic™ before it is placed in service.In the following equation, virtual output 3 is used as an input to both latch 1 and timer 1 as arranged in the order shownbelow:DIG ELEM 2 OPCont Ip H1c OnNOTAND(2)FLEXLOGIC ENTRY n:Virt Op 3 OnFLEXLOGIC ENTRY n:OR (4)FLEXLOGIC ENTRY n:LATCH (S,R)919293FLEXLOGIC ENTRY n:DIG ELEM 1 PKPFLEXLOGIC ENTRY n:XOR8990XORFLEXLOGIC ENTRY n:Virt Op 1 OnFLEXLOGIC ENTRY n:Virt Op 2 OnFLEXLOGIC ENTRY n:Virt Ip 1 On868788FLEXLOGIC ENTRY n:Virt Op 4 On85FLEXLOGIC ENTRY n:=Virt Op 499FLEXLOGIC ENTRY n:OR (3)FLEXLOGIC ENTRY n:TIMER 2969798FLEXLOGIC ENTRY n:Virt Op 3 OnFLEXLOGIC ENTRY n:TIMER 19495LATCHResetSetORORT1T2 VIRTUALOUTPUT 4827031A2.VSDFLEXLOGIC ENTRY n:Cont Ip H1c On
