DESCRIPTION OF INSTRUCTIONS33576. MUL AB (Multiply accumulator by B)1 0 1 0 0 1 0 07 0Instruction codeOperationsNumber of bytesNumber of cyclesFlags(PSW)DescriptionExample MUL AB(6AH × 15H=8B2H)Instruction code: Byte 1(A)0~7←(A) × (B)(B)8~15:C AC F0 RS1 RS0 OV F1 P• • •:::The accumulator contents are multiplied by the arithmeticoperation register (B) contents. The operand is always handledas an integer without sign. The lower order byte of the result isplaced in the accumulator, and the higher order byte is placedin the arithmetic operation register (B). The carry flag is alwayscleared. The overflow flag is set to 1 if the product is greaterthan 00FFH, and to 0 in all other cases.:141 0 1 0 0 1 0 07 0Byte 1Accumulator0 1 1 0 1 0 1 07 0Before executionAccumulator1 0 1 1 0 0 1 07 0After execution:Register B0 0 0 1 0 1 0 17 0Register B0 0 0 0 1 0 0 07 00Overflow flag1Overflow flag
